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| Math???? How do you mean!!! | | |
|  Zephyr-The-Zeph | Jan 13, 3:32pm | | Say, Hypothetically, Just for a moment here, You needed to solve the equations csc(x)^2=4, sin(x)^2-sin(x)=cos(x)^2, in 0 < x < 2pi, also, You need to find the angle of inclination of the line 3x+5y=13. What would you do? What steps would you take? What would be the answer? The survival of the human race depends on your trigonometric ability! |
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| | mgteixeira | Jan 16, 5:32am | | Is this going anywhere ? The angle of inclination is the inclination a plane (you have 2 variables xy). In your mathematical expressions you never identify Y. Are you sure you got the problem right ? what is the reactive function of Y to x ? |
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Sponsor |  eburgos | Feb 28, 6:59am | | The angle of inclination seems to be -3/5. A solution for the first one would be x=pi/6 since sin(x)=0.5. A solution for the other one can be pi/2 |
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|  ajinx999 | May 19, 4:57am | Let pi=p
[csx(x)]^2=4
csx(x)=±2
sin(x)=±0.5
The solutions for the equation are {p/6, 5p/6, 7p/6, 11p/6}
The equation,
[sin(x)]^2 - sin(x)=[cos(x)]^2
[sin(x)]^2 - sin(x)=1-[sin(x)]^2
2[sin(x)]^2 - sin(x)-1=0
This is a quadratic equation in sin(x)
Solving, the solutions obtained are {1, -0.5}
That is, sin(x)=1 or sin(x)=-0.5
Solving further, the solutions of the given equation come out to be {p/2, 7p/6, 11p/6}
3x+5y=13
The tangent of the angle of inclination of a line is the slope of the line. For the given linear equation, the easiest way to find slope is by converting the equation into 'slope-intercept' form of line, which is
y=mx+c ...(c is the y-intercept, m is the slope)
Therefore, the given equation in the above form would be
y=(-3/5)x+(13/5)
Hence, the slope of the line is -3/5.
And, the angle of inclination of the line is atan(-3/5). |
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| Math???? How do you mean!!! | | |
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